The sugar content of the syrup is canned peaches is normally distributed. assume the can is designed to have standard deviation 5 milligrams. a random sample of n = 10 cans is studied. what is the sampling distribution of the sample variance? the data yields a sample standard deviation of 4.8 milligrams. what is the chance of observing the sample standard deviation greater than 4.8 milligrams?

0.504772

Step-by-step explanation:

Given : The sugar content of the syrup is canned peaches is normally distributed. Assume the can is designed to have standard deviation milligrams.

A random sample of n = 10 cans is studied.

Then, the sampling distribution of the sample variance is chi-square () distribution witth degrees of freedom.

Sample standard deviation:  milligrams.

Test statistic for chi-square =

By using the chi-square distribution table , the chance of observing the sample standard deviation greater than 4.8 milligrams will be :-

P-value =

Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.504772

b and c

step-by-step explanation: