In applied life data analysis (wiley, 1982), wayne nelson presents the breakdown time of an insulating fluid between electrodes at 34kv. the times, in minutes, are as follows: 0.15, 0.75, 0.96, 1.35, 2.87, 3.19, 4.01, 4.62, 4.88, 6.43, 7.41, 8.04, 8.24, 12.86, 31.63, 32.61, 33.98, 36.18, and 72.83. calculate the sample mean and sample deviation of the breakdown data.

Mean = 14.3679

S.D = 18.83

Step-by-step explanation:

We are given the following data:

Time(minute)          

0.15,0.75,0.96,1.35,2.87,3.19,4.01,4.62,4.88,6.43,7.41,8.04,8.24,12.86,31.63,32.61,33.98,36.18,72.83

Formula:

Formula:

, where n is the total number of observations.

Sum of square of diffrences = 6386.57

S.D =

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this