The base of this regular right pyramid is a square.
what is its surface area?

○ C) 256 in.²

Step-by-step explanation:

{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256

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15

step-by-step explanation:

(-5,-28)

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