Igenuinely have no idea what this is asking from me
find the solution set of each equation if the replacement sets are y: {1,3,5,7,9}
and z: {10, 12, 14, 16, 18).
11. z + 10 = 22
12. 52 = 4z
13. (15/y) = 3
14. 17 = 24-y
15. 2z - 5 = 27
16. 4(y + 1) = 40
17. 22 = (60/y)+2
18. 111 = z^2 + 11

Step-by-step explanation:

Basically, it wants you to solve each equation for the variable.  If the answer(s) is one of the numbers in the replacement set, then that's a number in the solution set.  Otherwise, there's no solution.

For example:

11. z + 10 = 22

z = 12

12 is one of the numbers in the replacement set for z, so the solution set is {12}.

12. 52 = 4z

z = 13

13 is not one of the numbers in the replacement set for z.  There is no solution.

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

most likely linear (proportionate)

step-by-step explanation:

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