Give the general form of the equation of the line through (1,2) and is perpendicular to the line passing through (-6,-3)(6,3)

4x+3y-10=0

Step-by-step explanation:

first find the gradient of the line that is perpendicular to the line of interest.

y2-y1/x2-x1

3--3/6--6

=3+3/6+6

=9/12

3/4

The gradient of the line of interest is the negative reciprocal of 3/4. Therefore m is -4/3

next, substitute information into

y-y1=m(x-x1)

y-2=-4/3 (x-1)

multiply both sides of equation by 3

3y-6=-4 (x-1)

expand brackets

3y-6=-4x+4

rearrange in general form

4x+3y-10=0