Aline goes through the point (–4,–2) and has an x-intercept of –1. which point also lies on the line?

(0, 2/3) is another point on the line.

Step-by-step explanation:

The point  (-1, 0 ) is on the line ( that is the x-intercept).

The slope is (-2) / --4 - -1)

= -2/ -3 = 2/3.

So the equation of the line is

y - 0 = 2/3 (x - -1)

y = 2/3x + 2/3

When x = 0 y = 2./3 so another point on the line is (0, 2/3)

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)