[answer quickly ! ]
the nth term of a sequence is 9(n + 3).
what are the first four terms?
what is the 30th term?
which is the first term to be larger than 100?
the nth term of a sequence is n(n - 1).
what are the first four terms?
what is the 10th term?
is 51 a term in the sequence?
which term is 182?

30th term is

9(30+3) =270+27=297

to find the first term which is larger than 100

9(n+3) =100

9n=100-27

9n=73

n=73÷9

=8.1

so when n is>8.1 all the terms will be larger than 100 and the first term will be 9 since n can't be fraction as it's an ordinary number

so it's 9th

9(9+3) =81+27=108

the first four terms are

9(1+3) =36

9(2+3) =45

9(3+3) =81

9(4+3) =63

Step-by-step explanation:

n(n-1)

the first four terms are

1(1-1) =0

2(2-1) =2

3(3-1) =6

4(4-1) =12

the 10th term is 10(10-1) =90

to find weather 51 is a term or not

n(n-1) =51

n^2-n-51=0

1-4×1×-51=1+204=205

so it's roots will be fraction

so it's not from its terms because n will

be fraction

to find the term 182

n(n-1) =182

n^2-n-182=0

(n-14) (n+13)=0

so it's the term 14th because n can't be negative

nlgqer

step-by-step