James wants to compete in the international speed texting competition next year where participants compete on text speed and accuracy. james has found that his texting speed increases at a rate of 1/2 a character per second for each month that he practices.
1. a. what is james new texting speed if he practices for only for 1 month?
b. what is james new texting speed if he practices for 2 months?
c. what is his new texting speed if he practices for 3 months
write an algebraic equation that gives james texting speed s for m months of practice.
2. a. solve the equation from question 1d to determine how many months of practice it will take before james texting speed reaches 8 characters per second.
b. explain the steps to solve your equation from question 2a.
3. a. if lydia wants to text at least 8 characters per second like james then equation 10r + 4 = 8 could be used to model this situation. solve this equation for r.
b. explain what the variable r represents in the equation given in question 3.
4. consider the equation 8x + 5 = 37. write a real-life scenario that this equation could model.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation:

where is the diagram? shown below where? ?

step-by-step explanation: