Formulate the situation as a system of two linear equations in two variables. be sure to state clearly the meaning of your x- and y-variables. solve the system by the elimination method. be sure to state your final answer in terms of the original question. the concession stand at an ice hockey rink had receipts of $6200 from selling a total of 2600 sodas and hot dogs. if each soda sold for $2 and each hot dog sold for $3, how many of each were sold? sodas y = hot dogs x =

Let x be the number of sodas and y be the number of hot dogs.

Given : The concession stand at an ice hockey rink had receipts of $6200 from selling a total of 2600 sodas and hot dogs.

If each soda sold for $2 and each hot dog sold for $3.

Then we have a system of two linear equations in two variables :_

Multiply 2 to the each side of equation (1), we get

Eliminate equation (3) from equation (2), we get

Substitute the value of y in (1), we get

Hence,  1600 sodas and 1000 hot dogs were sold.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.