How do you do (a) and (b)?
bernoulli’s equation is an equation of the form y ′ = a(t)y + f(t)y n , where n can't be 0 or 1.
(a) using the substitution z = y 1−n , show that we can transform bernoulli’s equation into the linear equation z ′ = (1 − n)a(t)z + (1 − n)f(t).
(b) solve the equation xy′ + y = x^4 y^3

See solution below

Step-by-step explanation:

(a) If n=0 or 1, the equation

(1)  

would be a simple linear differential equation. So, we can assume that n is different  to 0 or 1.

Let's use the following substitution:

(2)

Taking the derivative implicitly and using the chain rule:

(3)

Multiplying equation (1) on both sides by

we obtain the equation

reordering:

Now, using (2) and (3) we get:

which is an ordinary linear differential equation with unknown function z(t).

(b)

The equation we want to solve is

(4)    

Here, our independent variable is x (instead of t)

Assuming x different to 0, we divide both sides by x to obtain:

Which is an equation of the form (1) with

So, if we substitute

we transform equation (4) in the lineal equation

(5)

and this is an ordinary lineal differential equation of first order whose

integrating factor is

but

Similarly,

and the general solution of (5) is then

where C is any real constant

Reversing the substitution  

we obtain the general solution of (4)

Attached there is a sketch of several particular solutions corresponding to C=1,4,6

It is worth noticing that the solutions are not defined on x=0 and for C<0

50x5=$250

step-by-step explanation:

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8