The construction shows angles cab and ide. there is a circle created from point a that intersects with ray ac, creating point f, and ray ab, creating point g. a circle congruent to circle a was created at point d. circle d intersects with ray de, creating point h. another circle was created on point h that has a radius that is congruent to the distance between points a and f. circle h intersects with circle d, creating point i. a ray was created through points d and i.
does the construction demonstrate how to copy an angle correctly using technology?
yes; the distance between points a and f was used to create circle h.
yes; the distance between points f and g was used to create circle h.
no; the distance between points a and f was used to create circle h.
no; the distance between points f and g was used to create circle h.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Just turn the whole gym into pie