Use the variation of parameters method to solve the de y"+y'- 2y=1

Step-by-step explanation:

Given differential equation is

   y"+y'-2y = 1

Hence, the characteristics is

=> D = -2, 1

The general equation of the given differential equation is

Let's consider that

g(t) = 1

Wronskian can be given by,

W = y_1(t)y'_2(t) - y_2(t)y'_1(t)

Now, the particular integral can be given by

Now,

Hence, the complete solution of the given differential equation is

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step-by-step explanation:

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