10. are the points a (3, 5), b (0, 2), and c (-2.10) the vertices of a right triangle? justify your
answer.

yes

Step-by-step explanation:

line ab^2=(3-0)^2+(5-2)^2=9+9=18

line bc^2=((0-(-2))^2+(2-10)^2=4+64=68

line ca^2=((-2)-3)^2+(10-5)^2=25+25=50

bc>CA>ab

if it's a right triangle, then bc^2=ab^2+ca^2

68=50+18

so, it's a right triangle

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.

20

step-by-step explanation: