Achemical company makes two brands of antifreeze. the first brand is 45% pure antifreeze and the second brand is 70% pure antifreeze. in order to obtain 150 gallons of a mixture that contains 55% pure antifreeze, how many gallons of each brand of antifreeze must be used?

60 gallons of 70% antifreeze

Step-by-step explanation:

Let n be the amount of 70% antifreeze. And the second brand was 45% pure anti freeze Then:

According to the question

0.7 n+.45(150-n)=0.55(150)

 0.7 n+67.5-0.45 n=82.5

0.25×n=15

n=15/.25 = 60

You need 60 gallons of 70% antifreeze, and 90 gallons of 45% antifreeze for this mixture

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6