After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 5.1 m/s2; after 3.6 s he enters the main speedway. at the same instant, another car on the speedway and traveling at a constant velocity of 71.3 m/s overtakes and passes the entering car. the entering car maintains its acceleration. how much time is required for the entering car to catch up with the other car?

The entering car is going to catch up with the other car after 20.76 seconds.

Step-by-step explanation:

The car leaving the pit area is moving with a constant accelaration, then we can calculate the speed it has when entering the main speedway using the following equation:

Where is the initial speed (which is zero given that the car starts froms rest), is the car's accelaration and is the time passed until it reaches the main speedway.

For an object travelling at a constant accelation, the displacement at a time can be calculate using the following equation:

(equation 1)

Let's consider the point where the first car enters the main speedway. If is the point where this car catch up with other one after seconds, we may rewrite the equation 1 like this:

(equation 2)

In other hand, the second car is travelling at a constant speed when it meets the entering car. Then, its displacement after seconds can be calculated using the following formula:

(equation 3)

The entering car is going to catch up with the other one when , so when can find how much time this will require equaling equations 2 and 3 and isolating

So, the entering car is going to catch up with the other car after 20.76 seconds.

your answer is the frist one

hop i

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice