Consider a rabbit population p(t) satisfying the logistic equation startfraction dp over dt endfraction equals ap minus bp squared , where upper b equals ap is the time rate at which births occur and upper d equals bp squared is the rate at which deaths occur. if the initial population is 220 rabbits and there are 9 births per month and 15 deaths per month occurring at time tequals0, how many months does it take for p(t) to reach 110% of the limiting population m?

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

same question do you know the answer

x=25tan30=14.43 or the answer is b

answer is your mom hey