Ajogger runs 140 m due west, then changes direction for the second leg of her run. at the end of the run, she is 374 m away from the starting point at an angle of 20o north of west. what were the length and direction of her second displacement?

The length of her second displacement = 247.12 m.

The direction of her second displacement = 31.24° from west.

Step-by-step explanation:

As per the question,

From the figure as drawn below,

Let the starting point be O. After running 140 m due west, she reached at point A.

∴ OA = 140 m

And At the end of the run, she is 374 m away from the starting point at an angle of 20° north of west.

∴ OP = 374 m

We have to find the distance AP = x.

By using the cosine rule in triangle OAP

After putting the given value, we get

  ∴ x = 247.12 m  

Hence,the length of her second displacement = 247.12 m.

Again,

By using the cosine rule in triangle OAP, we get

After putting the given value, we get

∴ α = 148.759°

Hence, the  direction of her second displacement = 180° - α = 180° - 148.759 = 31.24° from west.

understand that i don't know the answers

will someone answer his question

i saw this question before, dont know the asnwer srry

step-by-step explanation: