An airplane with room for 100 passengers has a total baggage limit of 6000 lb. suppose that the total weight of the baggage checked by an individual passenger is a random variable x with a mean value of 51 lb and a standard deviation of 23 lb. if 100 passengers will board a flight, what is the approximate probability that the total weight of their baggage will exceed the limit? (round the answer to four decimal places.)

The approximate probability that the total weight of their baggage will exceed the limit (6000 lb) is P=0.00005.

Step-by-step explanation:

To solve this problem, we have to think that we take a sample of 100 passengers, with a baggage weight that is a random variable normally distributed.

The parameters of the probability distribution of the sum of 100 normally distributed variables is:

Now we can calculate the probability of .

according to egenuity the answer is

step-by-step explanation:

d. 344.22

do you have a picture of the table