Suppose a statistics class contains five freshmen, ten sophomores, ten junior students, and ten senior students. randomly pick up 4 students from the class to form a study group. what is the probability that the study group contains exactly one freshman, one sophomore, one junior, and one senior?

The probability is 0.0955

Step-by-step explanation:

The number of ways in which we can select k elements from n elements in which the order is not important is given by combinations and it is calculated as:

So, the total number of ways in which we can select 4 students from the 35 in the statistics class are:

From this, the number of ways in which there are exactly one freshman, one sophomore, one junior and one senior are calculated as:

5C1 * 10C1 * 10C1 * 10C1 = 5,000

Because:

So, the probability is calculated as a division between the number of ways in which there are exactly one freshman, one sophomore, one junior and one senior and the total number of ways in which we can select 4 students from the 35 in the statistics class. This is:

-1/2 +2

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752