![\dfrac{\sqrt{3}}{\sqrt[4]{2}}](/tpl/images/0242/6525/705d9.png)
![\dfrac{\sqrt{3}}{\sqrt[4]{2}}\cdot\dfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}](/tpl/images/0242/6525/2e324.png)
![\dfrac{\sqrt{3}}{\sqrt[4]{2}}\cdot\dfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}=\dfrac{\sqrt{3}\sqrt[4]{2}}{\sqrt[4]{2\cdot 2^3}}=\dfrac{\sqrt{3}\sqrt[4]{2}}{\sqrt[4]{2^4}}=\dfrac{\sqrt{3}\sqrt[4]{2}}{2}](/tpl/images/0242/6525/e358d.png)
Rationalize the denominator.
sqrt(3)/(fourth root of 2)...
Answers: 1
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