the maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. a truck measures 162 inches in height. which best explaims whether or not the truck can pass safely under the bridge?
- the truck can pass safely under the bridge. the truck is 13 inches shorter than the maximum height
-the truck cannot pass safely under the bridge. the truck is 13 inches taller than the maximum height
- the truck can pass safely under the bridge. the truck is 12 inches shorter than the maximum height
-the truck cannot pass safely under the bridge. the truck is 12 inches taller than the maximum height

The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.

In the question,

The maximum height of the vehicle which is capable of passing under the bridge is 12 feet and 5 inches.

So,

Now we know that,

1 feet = 12 inches

So,

12 feet = 12 x 12 = 144 inches

So,

Total height of the vehicle which is permissible to pass under the bridge is,

12 feet 5 inches = 144 + 5 = 149 inches

Also,

Height of the truck = 162 inches

Therefore, we can see that the permissible height is smaller than the height of the vehicle.

Height of vehicle which is more than permissible height is by,

162 - 149 = 13 inches

Therefore, the truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.