Suppose that receiving stations x, y, and z are located on a coordinate plane at the points (9,5), (negative 9,negative 8), and (negative 9,2), respectively. the epicenter of an earthquake is determined to be 10 units from x, 13 units from y, and 13 units from z. where on the coordinate plane is the epicenter located?

Fun.  Let's renotate a bit and say we have A(9,5), B(-9,-8), C(-9,2) and seek P(x,y) such that

|AP|=10, |BP|=13, |CP|=13

It's an odd fact about geometry that squared distances are often algebraically more fundamental than distance.  In other words, we have

|AP|²=100, |BP|²=|CP|²=169

That tells us three equations, three circles whose meet we seek,

Three equations and two unknowns is an overdetermined system.  It may have no solution at all.  Let's solve the last two first.  Subtracting,

and factoring as the difference of two squares gives

That's two points of intersection of the last two circles,

We need to check if either of these satisfies the first equation.  (3, -3) first.

That one checks.  That's the answer.

(3,-3)

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

i can answer this question sweetie!

step-by-step explanation: