If a force f⃗ acts on an object as that object moves through a displacement s⃗ , the work done by that force equals the scalar product of f⃗ and s⃗ : w=f⃗ ⋅s⃗ . a certain object moves through displacement s⃗ =(4.00m)i^+(5.00m)j^. as it moves it is acted on by force f⃗ , which has x-component fx = -12.0 n (1 n = 1 newton is the si unit of force). the work done by this force is 26.0 n⋅m = 26.0 j (1 j = 1 joule = 1 newton-meter is the si unit of work). find the y-component of f⃗ .

Fy=14.8N

Step-by-step explanation:

the dot product between and

is given by:

W=

this gives the equation :

26= (4.00)(-12.0)+(5.00)Fy

26= -48+(5.00)Fy

adding 48 to both sides of the equation:

74= (5.00)Fy

dividing by 5, we get

Fy=74/5.00=14.8

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2