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Mathematics, 18.09.2019 00:30 amberc5110

What are the solutions to the equation?
x3+3x2βˆ’4xβˆ’12=0
x=
x=
x=
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Answers: 2

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What are the solutions to the equation?
x3+3x2βˆ’4xβˆ’12=0
x=
x=
x=
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