Will give
and explain how you get your
given: a(2,1), b(0,5), c(-1,2), ab and bc, mpab = 1/2, mpbc = -1/3, midpoint of ab = (1,3), midpoint of bc = (-1/2, 7/2).
find standard form equation of line perpendicular to bc through the
use the formula m= y-y1/x-x1
a) -x+2y=5
b) -x-2y= -5
c) -c-3y= -10
d) -x-2y=6
e) -x-3y=10

the answer is the third / last answer

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

where is the diagram? shown below where? ?

step-by-step explanation:

not me

step-by-step explanation:

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