In this problem, we will find the volume of a solid with circular base of radius 22, for which parallel cross-sections perpendicular to the base are squares. to do this, we will assume that the base is the circle x2+y2=4x2+y2=4, so that the solid lies between planes parallel to the xx-axis at x=2x=2 and x=−2x=−2. the cross-sections perpendicular to the xx-axis are then squares whose bases run from the semicircle y=−4−x2√y=−4−x2 to the semicircle y=4−x2√y=4−x2.

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

idkidkdidkdkdidkx

step-by-step explanation:

nndncnd cnn

snddnd

8

step-by-step explanation: