As soon as possible
the number of lattes sold daily for two coffee shops is shown in the table:
lattes
12
52
93
33
51
15
46
45
based on the data, what is the difference between the median of the data, including the outlier and excluding the outlier?
a.46
b.45.5
c.45
d.0.5

D

Step-by-step explanation:

First, we need to order the numbers from least to greatest. Let's do this:

12, 15, 33, 45, 46, 51, 52, 93

The median would be the average of 4th and 5th numbers [since there are 8 numbers, the median would be that of 8/2 = 4th and next, 5th number].

So 4th number is 45 and 5th number is 46, average would be (45+46)/2 =  45.5

Median = 45.5

Now, looking at the list the "outlier" would be "93". If we take this away, now we have:

12, 15, 33, 45, 46, 51, 52

Now, there are 7 numbers, and the median is the "middle" number, which is 4th number. This is the median, which is 45.

The difference, thus, is

45.5 - 45 = 0.5

Correct answer is D

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

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