Suppose that the central diffraction envelope of a double-slit diffraction pattern contains 15 bright fringes and the first diffraction minima eliminate (are coincident with) bright fringes. how many bright fringes lie between the first and second minima of the diffraction envelope?

6 bright fringes.

Step-by-step explanation:

We know bright interference fringes occur at

d sinθ =mλ where m is an integer.

Here d = 13×a/2(since there are 13 bright fringes ).

Then for first minimum which occurs at angle θ_1 then a sinθ_1 = λ (m=1)

for second minimum which occurs at angle θ_2 then a sinθ_2 = 2λ (m=2)

then we calculate the values of m for which  θ_1 < θ<  θ_2 for  sinθ_1 < sin_θ<  sinθ_2

λ < 2×mλ/13 <2λ

that is 1<2m/13 <2

the satisfied values of m are 7,8,9,10,11,.12. Thus there are 6 bright fringes.

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕

option a is correct.

step-by-step explanation:

scale factor: it is used to find proportional measurements.

proportions means having the same ratio.

scale factor is the ratio of the model measurement to the actual measurement in a simplest form.

or we can say that the ratio of any two corresponding lengths in two similar geometric figures

if the scale factor is more than 1, then it is an enlargement,

if the scale factor less than 1, then it is a reduction.

given the two geometric figure:

by definition of proportions, we have