Po is trying to solve the following equation by completing the square: 49x^2+56x-64 = 0. he successfully rewrites the above equation in the following form: (ax + b)^2 = c, where a, b, and c are integers and a > 0. what is the value of a + b + c?

The answer is 91

Step-by-step explanation:

We have the following equality:

Then a must satisfy that . So,

or .

1) If a=7, then, it follows for the first equality that 56=14b. Then b=4. Finally, substituting b=4 in the first equality we obtain that -64=16-c. So, c= 80. We conclude that

.

As the problem states, we only consider values of a greater than zero. Then 91 is the only solution for .

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =