If a tank fills in 4hours and empties in 6hours how long does it take if the tank is emptying and filling at the same time, how long will it take to be filled? this is all the info the problem has if you can figure it out ill give 100 points and the thing: )

12 hours.

Step-by-step explanation:

In 1 hour if the tap filling the tank runs on its own it will fill 1/4 of the tank. But if the tap that empties the tank is run at the same time it empties 1/6 of the tank. So the net result in 1 hour is that 1/4 - 1/6 = 1/12 of the tank is filled.

In the next hour the same thing happens - another 1/12 is filled.

So the tank will be filled in 12 hours.

Every hour, the tank would fill 1/4 of the way, but it would be set back by 1/6 of it's original progress due to the emptying. So how much progress did it actually make in that hour? 1/4 - 1/6 = 0.08333333. It filled 0.0833...%

This would mean '1' = 100%, so we have the equation 0.0833... x ? = 1

Well, 0.083333 is equal to the fraction 1/12. Also, 0.083333 x 12 equals 1. You can take either of those two routes to find your answer, but we can tell either way that it takes 12 hours.

answer: idk

step-by-step explanation:

c = 0.429t

step-by-step explanation:

the constant rate at which carlos harvests cassava is 35 minutes per 15 cassavas 15/35 = 0.429 cassava per minute

therefore, an equation that models the number of cassava (c) that harvest carlos in a time (t) is the following:

where t is the time in minutes.

this means that when 35 minutes have elapsed 15 cassava have been harvested, at 70 minutes 30 cassava have been harvested and so on.