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Mathematics, 16.09.2019 03:30 s11632270

Por favor que alguien me ayude con
(4/7) (βˆ’3/5)=
(3/5) (βˆ’6/7) (βˆ’4) =
6Γ·1/8=
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Answers: 1

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Por favor que alguien me ayude con
(4/7) (βˆ’3/5)=
(3/5) (βˆ’6/7) (βˆ’4) =
6Γ·1/8=
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