1.84repeating as a mixed number in simplest form

Hello!

I'm assuming you're looking for 1.848484.

The first thing we want to do is get rid of the repeating part. The way we can do this is subtract the number we are given from itself multiplied by a power of 10. So, set 1.8484... = x. And based off of that, find 100x. This is because the next time the decimal repeating will become .8484 again is after two numbers pass.

1.848484... = x

184.8484... = 100x

Next, subtract x from 100x. This will get rid of the repeating decimal.

100x - x = 184.8484... - 1.8484

99x = 183

Finally, divide both sides by 99. This leaves us with a fraction.

99x = 183

x = 183 / 99

Simplify this fraction.

183 / 99 -> 61 / 33

Finally, turn it into a mixed number, as this is the form your question is looking for.

61/33 -> 1 28/33

Hope this helps!

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

0.32

step-by-step explanation:

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