Find the coordinates of the vertices of the figure after the given transformation, translation: (x, y)→(x - 4, y + 4)
a) j'(1, 0), n'(5, 0), m'(5, 3), p'(2, 5)
b) j'(-2, 5), n'(2, 5), m'(2, 2), p'(-1, 0)
c) j'(-3, 4), n'(1, 4), m'(1, 1), p'(-2, -1)
d) j'(-1, 0), n'(-5, 0), m'(-5, -3), p'(-2, -5)

Option C J'(-3, 4), N'(1, 4), M'(1, 1), P'(-2, -1)

Step-by-step explanation:

we know that

The rule of the translation is

(x,y) > (x-4,y+4)

That means > The translation is 4 units at left and 4 units up

Find out the coordinates of the pre-image

Observing the figure

J(1,0),N(5,0),M(5,-3),P(2,-5)

Find out the coordinates of the image

Applying the rule of the translation at the coordinates of pre-image

J(1,0) > J'(1-4,0+4)

J(1,0) > J'(-3,4)

N(5,0) ---> N'(5-4,0+4)

N(5,0) ---> N'(1,4)

M(5,-3)> M'(5-4,-3+4)

M(5,-3)> M'(1,1)

P(2,-5) > P'(2-4,-5+4)

P(2,-5) > P'(-2,-1)

therefore

The coordinates of the image (after the transformation) are

J'(-3, 4), N'(1, 4), M'(1, 1), P'(-2, -1)

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

4.

step-by-step explanation:

it have the same area.brainliest