The constant-pressure specific heat of air at 25°c is 1.005 kj/kg. °c. express this value in kj/kg. k, j/g.°c, kcal/ kg. °c, and btu/lbm-°f.

In kJ/kg.K - 1.005  kJ/kg degrees Kalvin.

In  J/g.°C  -  1.005 J/g °C

In kcal/ kg °C  0.240 kcal/kg °C

In Btu/lbm-°F   0.240 Btu/lbm degree F

Step-by-step explanation:

given data:

specific heat of air = 1.005 kJ/kg °C

In kJ/kg.K

1.005 kJ./kg °C = 1.005 kJ/kg degrees Kalvin.

In  J/g.°C

In kcal/ kg °C

For   kJ/kg. °C to Btu/lbm-°F  

Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.

1.005 kJ/kg C =  0.240 Btu/lbm degree F

answer: 2 answers

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