To determine the order that cars line up for the daytona 500, drivers must complete qualifying laps around the daytona international speedway. the fastest ever qualifying lap was in 1987 by bill elliott, with a time of 42.782 seconds. that was 210.364 miles per hour (or 338.548 kilometers per hour).
a. what was the frequency of the car (measured in laps per second? )
b. how many laps were completed in 60 seconds (1 minute)?

The frequency of the car is 0.0233743 laps/sec and 1.4024 laps were completed in 60 seconds

Step-by-step explanation:

We are given that he fastest ever qualifying lap was in 1987 by Bill Elliott, with a time of 42.782 seconds.

No. of laps completed in 42.782 seconds. = 1

No. of laps completed in 60 seconds. =

                                                                =

Hence the frequency of the car is 0.0233743 laps/sec and 1.4024 laps were completed in 60 seconds

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer

answer: slight chance that it will happen

step-by-step explanation: