Awind turbine is located at the top of a hill where the wind blows steadily at 12 m/s, and stands 37 m tall. the air then exits the turbine at 9 m/s and the same elevation. find the power generated by the wind if the mass flow rate is 137 kg/s. report your answer in kw and to 2 decimal places.

4.3155 kW

Step-by-step explanation:

Given,

speed of wind when enters into the turbine, V = 12 m/s

speed of wind when exits from the turbine, U = 9 m/s

mass flow rate of the wind = 137 kg/s

According to the law of conservation of energy

Energy generated = change in kinetic energy

Hence,energy generated in 1 sec can be given by

    = 4315.5 J

So, the power generated in 1 sec will be given by

    = 4315.5 W

    = 4.13 kW

So, the power generated will be 4.13 kW.

the function makes a strait line horizontally with no x intercept but a y intercept at 9.

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.