Arectangle field has a perimeter of 220 meters and an area of 2856 square meters. what are the dimensions?

The dimensions are 68 meters by 42 meters.

Step-by-step explanation:

Let the length be x

Let the width be y

Perimeter = 220 meter

So,

or or    ...........(1)

Area = 2856 square meter

So,     ............(2)

Substituting the value of x from (1) in (2)

=>

=>

Solving this equation, we get roots as y = 68 and y = 42

So, if we put y = 68, we get x = 42

If we put y = 42, we get x = 68

As length is longer than width, we will take length = 68 meters and width = 42 meters.

Hence, the dimensions are 68 meters by 42 meters.

y -5 = (-1/4)(x + 8)

step-by-step explanation:

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation: