For each of the two sets of numbers below, determine whether it is a field. if it is a field, just write it is a field. if it is not a field, write it is not a field, state which of the field properties does not hold and give an example showing this (a) f ={a+bv/2 a, bz that is, f is the set of all umbers of the form a+ by/2, where a and b are integers.

the square root of what number? if you add that, then someone will probably answer the question.

0.32

step-by-step explanation:

2.24/7

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.