Show that the given curve c(t) is a flow line of the given velocity vector field f(x, y, z).
c(t) = (t^2, 2t − 6, 3sqrt( t > 0; f(x, y,z) = ( y+6, 2, 9/2z)
c'(t) = ?
f(c(t)) = ?

The given curve c(t) is a is a flow line of given velocity vector field F(x, y, z).

Step-by-step explanation:

We are given the following information in the question:

Now, we evaluate the following:

Now, we have to evaluate:

When F(c(t)) = c'(t), then c(t) is a flow line of given velocity vector field F(x, y, z).

Since, , we can say that c(t) is a flow line of given velocity vector field F(x, y, z).

no idea

step-by-step explanation:

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant