Consider an elastic string of length l whose ends are held fixed. the string is set in motion from its equilbiu position with an initial velocity u,(x,0)-g(r). in each of problems 5 through 8, carry out the following steps. let l 10 and a-1 in parts (b) through (d). (a) find the displacement u(x, t) for the given g(x) (b) plot 11(x, t) versus x for 0 x 10 and for several values of t between t = 0 and t = 20. (c) plot u(x, t) versus t for 0 t320 and for several values of x. (d) construct an animation of the solution in time for at least one period. (e) describe the motion of the string in a few sentences. 2x/l 2(l - x)/l, l/2

you can't solve x because it is 2 linear equation and you only have one equation

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

happy to

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answer: the answer is b. i think hope i got it correct

step-by-step explanation: