In module 1 you drew a plot of the heat distribution over a steel plate, given by u(x, y) = 8oy2e-r2-0.3y2 plot this surface over the domain -2.1

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

it would open into a square depending on the type of envelope i’m not sure about the second part

the correct answers i think are b. and d.

give me brainliest if it is correct!