Let a and b be non-empty, bounded subsets of r. (a) why does sup(aub) exist? (b) prove that sup(aub) = max{sup a, sup b}.

Answer with Step-by-step explanation:

Let A and B be non- empty bounded subset of R

a.We have to find why exist

If A and B are bounded set

Then there exist  constant  such that

and

Then , sup of A =b and sup of B=d

When  a set is bounded then all elements lie in the set are lie between the constants s and t.

All elements are less than or equal to t then t is supremum of set.

Because both set are bounded and sup of both set A and B are exist.All elements A union B are less than or equal to sup A or sup B.

Then, exist.

b.We have to prove that

Suppose ,A =(1,2) and B=(2,3)

Sup A=2 , sup B=3

Upper bound of

Hence,

If A=(4,5),B=(2,3)

Sup A=5,Sup B=3

Hence,

Hence, we can say that .

90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

Step-by-step explanation:

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )