We now have an algebraic expression with only one variable, which can be solved. once we have that, we can plug it back into one of the original equations (or the expression derived in part a) to solve for the other variable. when this is done with the system of two equations from parts a and b, what is the solution? enter a, then b, as two numbers, separated by a comma.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it

add 8+12 to get a simplified answer of 12r-20