Aclassroom has ten students. three students are freshman, two are sophomores, and five are juniors. three students are randomly selected (without replacement) to participate in a survey. consider the following events: a = exactly 1 of the three selected is a freshman b = exactly 2 of the three selected are juniors find the following probability. if needed, round to four decimal places. pr(a∩b) =

0.25

Step-by-step explanation:

We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.

On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by

(3C1)(5C2)=(3)(10)=30 and

Pr(A∩B)=30/120=0.25

146 days

step-by-step explanation:

1. (365*2)/5 =

730/5 =

146 days

2. 365/5=

73*2   = 146

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step-by-step explanation: