Amanufacturer of pickup trucks is required to recall all the trucks manufactured in a given year for the repair of possible defects in the steering column and defects in the brake linings. dealers have been notified that 3% of the trucks have defective steering only, and that 6% of the trucks have defective brake linings only. if 87% of the trucks have neither defect, what percentage of the trucks have both defects?

Probability of trucks having both defects is 4%.

Step-by-step explanation:

Since we have given that

Probability of trucks having defective brake linings only = 6%

Probability of trucks having defective steering only = 3%

Probability of trucks having neither defect = 87%

Probability of trucks having either defect - 100 - 87 = 13%

Let the probability of trucks having both defects be 'x'.

P(defective brake lining) = P(B) = 0.06+x

P(defective steering) = P(S) = 0.03+x

So, Probability of the trucks having both defects is given by

So, Probability of trucks having both defects is 4%.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a

step-by-step explanation: