What is the domain of the function
f(x)= square root of (1/3)x+2?

The domain of f(x) = √[(1/3)x +2] is [-6, ∞).

Step-by-step explanation:

GIven f(x) = √[(1/3)x +2], you have to find the values for which the the expression inseide the square will be possitive (for negative values the function is not defined for Reals.

(1/3)x + 2 = 0 ⇒ (1/3)x = -2 ⇒ x = -2/(1/3) ⇒ x = -6

Finally the domain of f(x) is (-6, ∞).

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

y > 1/3x

y < = -x + 4

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