Two boats leave port at the same time. one goes west and the other south. the speed of the southbound boat is 5 mph more than the westbound boat. after 3 hours the boats are 27 miles apart. find the speed of the southbound boat. round to the nearest tenth of a mile per hour.

Westbound boats speed = X

Southbound boats speed = X + 5

In 3 hours they are 27 miles apart:

3X + 3(x+5) = 27

Simplify:

3x + 3x +15 = 27

Combine like terms:

6x + 15 = 27

Subtract 15 from both sides:

6x = 12

Divide both sides by 6:

x = 12/6

x = 2

Westbound was 2 miles per hour

Southbound was 2 +5 = 7 miles per hour

Check:

2 miles per hour x 3 hours = 6 miles

7 miles per hour x 3 hours = 21 miles

21 + 6 = 27 miles

the answer will be b x² +x-1

step-by-step explanation:

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,