Arectangle has a length of x+7 and a width of 2x-3. if it’s perimeter is 32, what is the value of 3x? a.4/b.12/c.14/d.36/e.42/

The correct option is C. 14.

Step-by-step explanation:

First you have that the perimeter of a rectangle = (2·length) + (2·width)

⇒perimeter of a rectangle = [2·( x + 7)] + [2·(2x - 3)]

⇒ 32 = [2·( x + 7)] + [2·(2x - 3)] ⇒ 32 = (2x + 14) + (4x - 6)

⇒ 32 = 6x + 8 ⇒ 32 - 8 = 6x ⇒ 24= 6x ⇒ 24/6 = x ⇒ x = 4. ⇒ 3x= 12.

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

1 is c

2 is a

3 is a

step-by-step explanation: