The line segment ef has a midpoint with coordinates m (-2,2). use the formula to find the coordinates of the other endpoint given that e is located at coordinates (2,8).

The answer to your question is:   F = (-6, -4)

Step-by-step explanation:

Segment = EF

mpM = (-2, 2)

first point = E = (2, 8)

second point = F = (x, y)

Formula

      Xmp = (x1 + x2) / 2                         Ymp = (y1 + y2) / 2

      x2 = 2xmp - x1                                y2 = 2ymp - y1

Process

     x2 = 2(-2) - 2                                   y2 = 2(2) - 8

     x2 = -4 - 2                                       y2 = 4 - 8

     x2 = -6                                            y2 = -4

                     F = (-6, -4)

i can't see the picture : /

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3