Answers: 2
![\sqrt{3]{x} - 8](/tpl/images/0227/4574/cc5ab.png)
is 
, basically, we have to reverse r. We exchange y and x in their positions, and then we have to isolate y.![y = \sqrt[3]{x} - 8](/tpl/images/0227/4574/a253c.png)
![x = \sqrt[3]{y} - 8](/tpl/images/0227/4574/dfb4f.png)
![x + 8 = \sqrt[3]{y}](/tpl/images/0227/4574/e5e0c.png)
![(x+8)^{3} = (\sqrt[3]{y})^{3}](/tpl/images/0227/4574/21fb5.png)
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